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Proof step 4 from proof oc-del-01 (previous step)

#oc(a, x) + #oc(a, y) = m + 1, a ∈ y ⊦ #oc(a, (x + y) -1l a) = m, #oc(a, x) + #oc(a, y) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
#oc(a, x) + #oc(a, y) = m + 1, a ∈ y ⊦ #oc(a, (x + y) -1l a) = m

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + 1 ≠ 0; (s)