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Proof step 3 from proof oc (previous step)

#oc(a, y) < #oc(a, x), ∀ a. #oc(a, x) ≤ #oc(a, y) ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: a

Additional information

Used simplifier rules: fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat% ⊦ ¬ n < n; (s) Used terms: a