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Proof step 1 from proof ocnodups-01 (conclusion)
⊦ ¬ dups(x) → (1 ≤ #oc(a, x) ↔ a ∈ x)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
⊦ 1 ≤ #oc(a, x) ↔ a ∈ x, dups(x)
Rule argument
Additional information