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Proof step 3 from proof ocs-del-length (previous step)

⊦ #oc(a, x -l b) = #oc(a, x), a = b

User applied rule structural induction

And obtained the following new goals

Proof step 4:
∀ a, b. #oc(a, x0 -l b) = #oc(a, x0) ∨ a = b ⊦ #oc(a, (a0 + x0) -l b) = #oc(a, a0 + x0), a = b

Rule argument

indvar: x

Additional information

Used simplifier rules: oc-e: ⊦ #oc(a, []) = 0;%list freely generated by [], +;;% ⊦ [] -l a = []; (s)