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Proof step 10 from proof ocs-dups-ex (previous step)

∀ a1. a1 ∈ x0 → #oc(a1, x0) = 1, a = a0 ∨ a ∈ x0 ⊦ dups(x0), a0 ∈ x0, a ≠ a0 ∧ #oc(a, x0) = 1, ¬ a ∈ x0 ∧ #oc(a, a0 ') = 1

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 11:
∀ a1. a1 ∈ x0 → #oc(a1, x0) = 1, a = a0 ∨ a ∈ x0 ⊦ a = a0, dups(x0), a0 ∈ x0, ¬ a ∈ x0 ∧ #oc(a, a0 ') = 1, a ≠ a0 ∧ #oc(a, x0) = 1

Rule argument

fma: a = a0

Additional information

Used simplifier rules: one: ⊦ #oc(a, a ') = 1; Used formulas: a = a0