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Proof step 12 from proof ocs-same-length-mklist (previous step)

#oc(a, x0) = 1 + # x0, ∀ a. #oc(a, x0) = # x0 ↔ x0 = mklist(a, # x0) ⊦ a = a0

User applied rule insert lemma

And obtained the following new goals

Proof step 13:
⊦ ¬ # x < #oc(a, x)
Proof step 14:
#oc(a, x0) = 1 + # x0, ∀ a. #oc(a, x0) = # x0 ↔ x0 = mklist(a, # x0) ⊦ a = a0, # x0 < #oc(a, x0)

Rule argument

spec: <toplevel> name: ocs-not-more seq: ⊦ ¬ # x < #oc(a, x) subst: [x, a] → [x0, a]

Additional information

Used terms: x0, a