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Proof step 20 from proof ocs-sw (previous step)

n < # x, m < # x, n < # x[m, x[n]] ⊦ #oc(a, x[m, x[n]]) = #oc(a, x), x[m, x[n]][n] = a, a = x[m], x = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
m < # x, n < # x ⊦ #oc(a, x[m, x[n]]) = #oc(a, x), x[m, x[n]][n] = a, a = x[m], x = []

Rule argument

Additional information

Used simplifier rules: ⊦ n < # x → # x[n, a] = # x; (s)