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Proof step 3 from proof perm-dups-02 (previous step)

dups(y), perm(x, y + z), perm(y + z, x) ⊦ dups(x)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: perm-dups-01 seq: ⊦ dups(x) ∧ ¬ dups(y) → ¬ perm(x, y) subst: [y, x] → [x, y + z] flags: <all paths>

Additional information

Used simplifier rules: ⊦ dups(x) → dups(x + y); (s)%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: x, y + z