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Proof step 5 from proof perm-put (previous step)

n < # y, perm(x, y[n, a]), perm(y[n, a], x) ⊦ y = [], a ∈ x ∧ perm(x -1l a, y -1l y[n])

Heuristic pl case distinction applied rule case distinction

And obtained the following new goals

Proof step 6:
n < # y, perm(y[n, a], x), perm(x, y[n, a]) ⊦ y = [], a ∈ x
Proof step 8:
n < # y, perm(y[n, a], x), perm(x, y[n, a]) ⊦ y = [], perm(x -1l a, y -1l y[n])

Rule argument

pos: right 2

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