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Proof step 1 from proof perm-rmv-in (conclusion)

⊦ perm(x + (a + y), x0 + (a + y0)) ↔ perm(x + y, x0 + y0)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: perm-rmv-in-list: ⊦ perm(x + a ' + y, x0 + a ' + y0) ↔ perm(x + y, x0 + y0);%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ a + x = a ' + x; (s)