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Proof step 10 from proof size-perm (previous step)

# x = # y, ∀ a. a ∈ y → a ∈ x, ∀ a. a ∈ x → a ∈ y ⊦ dups(y), dups(x), #oc(a0, y) ≤ #oc(a0, x)

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 11:
# x = # y, a0 ∈ x → a0 ∈ y, ∀ a. a ∈ x → a ∈ y, ∀ a. a ∈ y → a ∈ x ⊦ dups(x), dups(y), #oc(a0, y) ≤ #oc(a0, x)

Rule argument

pos: left 3 terms: a0

Additional information

Used terms: a0