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Proof step 6 from proof size-perm (previous step)

# x = # y, ∀ a. a ∈ y → a ∈ x, ∀ a. a ∈ x → a ∈ y ⊦ dups(y), dups(x), #oc(a, x) ≤ #oc(a, y) ∧ #oc(a0, y) ≤ #oc(a0, x)

User applied rule case distinction

And obtained the following new goals

Proof step 7:
# x = # y, ∀ a. a ∈ x → a ∈ y, ∀ a. a ∈ y → a ∈ x ⊦ dups(x), dups(y), #oc(a, x) ≤ #oc(a, y)
Proof step 9:
# x = # y, ∀ a. a ∈ x → a ∈ y, ∀ a. a ∈ y → a ∈ x ⊦ dups(x), dups(y), #oc(a0, y) ≤ #oc(a0, x)

Rule argument

pos: right 3

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