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Proof step 8 from proof subapp-02 (previous step)

#oc(a, x0) + #oc(a, y) < #oc(a, x), a ∈ x, ∀ a. #oc(a, x) ≤ #oc(a, x0) ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a

Additional information

Used simplifier rules: fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat% ⊦ ¬ m + n < m; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used terms: a