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Proof step 2 from proof subapp (previous step)

x ⊆m x0, y ⊆m y0 ⊦ x + y ⊆m x0 + y0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
y ⊆m y0, x ⊆m x0 ⊦ x + y ⊆m x0 + y0

Rule argument

Additional information