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Proof step 3 from proof subdel-01 (previous step)

a ∈ y0, x ⊆m y + (y0 -1l a) ⊦ x ⊆m (y + y0) -1l a

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ x ⊆m y ↔ (∀ a. #oc(a, x) ≤ #oc(a, y))
Proof step 5:
a ∈ y0, x ⊆m y + (y0 -1l a) ⊦ ∀ a0. #oc(a0, x) ≤ #oc(a0, (y + y0) -1l a)

Rule argument

spec: <toplevel> name: msubset seq: ⊦ x ⊆m y ↔ (∀ a. #oc(a, x) ≤ #oc(a, y)) subst: [y, x] → [(y + y0) -1l a, x] flags: <all paths>

Additional information

Used terms: (y + y0) -1l a, x