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Proof step 15 from proof subrec (previous step)

a ∈ y, ∀ a0. #oc(a0, x) ≤ #oc(a0, y -1l a) ⊦ ∀ a0. #oc(a0, a ') + #oc(a0, x) ≤ #oc(a0, y)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
#oc(a0, y) < #oc(a0, a ') + #oc(a0, x), a ∈ y, ∀ a0. #oc(a0, x) ≤ #oc(a0, y -1l a) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)