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Proof step 12 from proof trans (previous step)

#oc(a0, x) < #oc(a0, z), #oc(a0, x) < #oc(a0, y), a0 ∈ z, a0 ∈ y, #oc(a0, z) ≤ #oc(a0, y), ∀ a. #oc(a, y) ≤ #oc(a, z), ∀ a. #oc(a, z) ≤ #oc(a, y), ∀ a. #oc(a, x) ≤ #oc(a, y), ∀ a. #oc(a, y) ≤ #oc(a, x) ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 9 terms: a0

Additional information

Used simplifier rules: ⊦ m ≤ n → (n < m ↔ false); (s) Used terms: a0