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Proof step 9 from proof trans (previous step)

#oc(a, z) < #oc(a, x), #oc(a, z) < #oc(a, y), a ∈ x, a ∈ y, #oc(a, x) ≤ #oc(a, y), ∀ a. #oc(a, y) ≤ #oc(a, z), ∀ a. #oc(a, z) ≤ #oc(a, y), ∀ a. #oc(a, x) ≤ #oc(a, y), ∀ a. #oc(a, y) ≤ #oc(a, x) ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: a

Additional information

Used simplifier rules: ⊦ m ≤ n → (n < m ↔ false); (s) Used terms: a