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Proof step 10 from proof diffgetn-nodupssize (previous step)

n ≤ # x0, ∀ m0, n0. # x0 = m0 + 1 ∧ n0 ≤ m0 → #(x0 \ x0[n0] ') = m0 ∨ x0 = [] ⊦ 1 + #(x0 \ (a ' + x0)[n] ') = # x0, a = (a ' + x0)[n], x0 = [], dups(x0), a ∈ x0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
n ≤ # x0, ∀ m, n0. # x0 = m + 1 ∧ n0 ≤ m → #(x0 \ x0[n0] ') = m ⊦ 1 + #(x0 \ (a ' + x0)[n] ') = # x0, a = (a ' + x0)[n], x0 = [], dups(x0), a ∈ x0

Proof step 10 from proof diffgetn-nodupssize (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information