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Proof step 1 from proof k-union-rec-n (conclusion)

⊦ ¬(a ∈ x ∨ a ∈ y) → (a + x) ∪ y = a + (x ∪ y)

System applied rule normalize

And obtained the following new goals

Proof step 2:
⊦ (a + x) ∪ y = a + (x ∪ y), a ∈ x, a ∈ y

Rule argument

Additional information