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Proof step 1 from proof append-size-less (conclusion)
⊦ # x < # x1 → (x + x0 = x1 + x2 ↔ (∃ y. x1 = x + y ∧ x0 = y + x2))
System applied rule normalize
And obtained the following new goals
Proof step 2
:
# x < # x1 ⊦ x + x0 = x1 + x2 ↔ (∃ y. x1 = x + y ∧ x0 = y + x2)
Rule argument
Additional information