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Proof step 1 from proof eq-01 (conclusion)

⊦ x + a ' + y = b ' + z ∧ x + a ' + y0 = b0 ' + z0 → b = b0

System applied rule normalize

And obtained the following new goals

Proof step 2:
x + a ' + y = b ' + z, x + a ' + y0 = b0 ' + z0 ⊦ b = b0

Rule argument

Additional information