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Proof step 2 from proof fr (previous step)

⊦ x.head ' + x.tail = x, x = []

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: One: ⊦ a ' = a + [];%Cons: ⊦ (a + x) + y = a + (x + y);%Nil: ⊦ [] + x = x;% ⊦ x ≠ [] → x.head + x.tail = x; (s)