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Proof step 2 from proof in-10 (previous step)

⊦ a ∈ b ' + x ↔ a = b, a ∈ x

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: in-append: ⊦ a ∈ x + y ↔ a ∈ x ∨ a ∈ y;%in-17: ⊦ a ∈ b ' ↔ a = b;%a: ⊦ (x + y) + z = x + y + z;