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Proof step 2 from proof in-16 (previous step)

x + a ' = y + b ' + z ⊦ a = b, a ∈ z

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ni: ⊦ x + a ' = y + z ∧ ¬ a ∈ z → z = [];%a: ⊦ (x + y) + z = x + y + z;%in-15: ⊦ x + a ' = y → a ∈ y;%app: ⊦ x + [] = x;%app-06: ⊦ x + a ' = y + b ' ↔ x = y ∧ a = b;