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Proof step 3 from proof inapp-07 (previous step)

b ' + x = y + b ', b ∈ x ⊦ x = [], b ∈ y

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: y

Additional information

Used simplifier rules: Nil: ⊦ [] + x = x;%a: ⊦ (x + y) + z = x + y + z;%c-03: ⊦ a ' = b ' + x ↔ a = b ∧ x = [];%c: ⊦ a + x = a ' + x;%a: ⊦ (x + y) + z = x + y + z;%c-06: ⊦ a ' + x = b ' + y ↔ a = b ∧ x = y;%in-rec: ⊦ a ∈ b ' + x ↔ a = b ∨ a ∈ x;%list freely generated by [], +;;