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Proof step 2 from proof inex-03 (previous step)

x + a ' = y ⊦ ∃ y0. y = y0 + a '

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: app-03: ⊦ x + y = z + y ↔ x = z;%a: ⊦ (x + y) + z = x + y + z;