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Proof step 7 from proof lastdiv (previous step)

⊦ ∃ y0, a1. a ' + y + a0 ' = y0 + a1 '

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: a + y, a0

Additional information

Used simplifier rules: c: ⊦ a + x = a ' + x;%a: ⊦ (x + y) + z = x + y + z;%app-07: ⊦ a ' + x = b ' + x ↔ a = b; Used terms: a + y, a0