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Proof step 5 from proof len-06 (
previous step
)
# y = # y0, x + y = z + y0, # x = # z → (x + y = z + y0 ↔ x = z ∧ y = y0) ⊦ x = z ∧ y = y0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
# y = # y0, x + y = z + y0 ⊦ # x = # z
Rule argument
Additional information