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Proof step 1 from proof neq-04 (conclusion)

⊦ a ∈ y0 ∧ ¬ a ∈ y ∧ a ≠ b → y + b ' ≠ y0 + c ' + z

System applied rule normalize

And obtained the following new goals

Proof step 2:
y + b ' = y0 + c ' + z, a ∈ y0 ⊦ a = b, a ∈ y

Rule argument

Additional information