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Proof step 10 from proof fixpoint-nu (previous step)

monotone(f) ⊦ f(ν(f))(x) ↔ f(λ x0. ¬ μ(compl(f))(x0))(x)

User applied rule cut formula

And obtained the following new goals

Proof step 11:
monotone(f) ⊦ f(ν(f))(x) ↔ f(λ x0. ¬ μ(compl(f))(x0))(x), ν(f) = (λ x0. ¬ μ(compl(f))(x0))

Rule argument

fma: ν(f) = (λ x0. ¬ μ(compl(f))(x0))

Additional information

Used formulas: ν(f) = (λ x0. ¬ μ(compl(f))(x0))