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Proof step 2 from proof mu-is-IS (
previous step
)
monotone(f) ⊦ μ(f) = IS(λ S. f(S) ⊆ S)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
monotone(f) ⊦ μ(f) = IS(λ S. f(S) ⊆ S)
Rule argument
Additional information