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Proof step 11 from proof nu-is-UN (previous step)

monotone(f) ⊦ ¬ μ(compl(f))(x) ↔ (∃ S. S ⊆ f(S) ∧ S(x)), monotone(compl(f))

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: compl-monotone seq: ⊦ monotone(f) → (monotone(compl(f)) ↔ true) subst: [f] → [f] flags: <all paths>

Additional information

Used terms: f