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Proof step 27 from proof nu-is-UN (
previous step
)
monotone(f), monotone(compl(f)), ∀ S. compl(f)(S) ⊆ S → S(x), ∃ S. S ⊆ f(S) ∧ S(x) ⊦
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 28
:
S(x), monotone(compl(f)), monotone(f), S ⊆ f(S), ∀ S. compl(f)(S) ⊆ S → S(x) ⊦
Rule argument
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