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Proof step 1 from proof subset-trans (conclusion)
⊦ S ⊆ S0 ∧ S0 ⊆ S1 → S ⊆ S1
System applied rule normalize
And obtained the following new goals
Proof step 2
:
S ⊆ S0, S0 ⊆ S1 ⊦ S ⊆ S1
Rule argument
Additional information