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Proof step 2 from proof even-02 (previous step)

m + m < n + n, n < m ⊦ n + n = 0, m = n, m = 0

User applied rule structural induction

And obtained the following new goals

Proof step 3:
n < m0 +1, m0 +1 + m0 +1 < n + n, ∀ n. m0 + m0 < n + n ∧ n < m0 → n + n = 0 ∨ m0 = n ∨ m0 = 0 ⊦ n + n = 0, m0 +1 = 0, m0 +1 = n

Rule argument

term: m

Additional information

Used simplifier rules: gen: ⊦ ;