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Proof step 7 from proof l-05 (previous step)

n + n0 < m, m + m1 + 1 < n, ∀ m, n, n0. m + m1 < n ∧ n + n0 < m → m = 0 ∨ n = 0 ⊦ m = 0, n = 0, m + m1 < n

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: n, n0, m

Additional information

Used simplifier rules: nls-fst: ⊦ ¬ m < n → ¬ m + m0 < n;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m; Used terms: n, n0, m