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Proof step 2 from proof l (previous step)

∀ m, n. m + n < m + n1 ↔ n < n1 ⊦ m + n < m + n1 +1 ↔ n < n1 +1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ m, n. m + n < m + n1 ↔ n < n1 ⊦ m + n < m + n1 + 1 ↔ n < n1 + 1

Rule argument

Additional information

Used simplifier rules: succ: ⊦ m +1 = m + 1;%a: ⊦ (m + n0) + n1 = m + n0 + n1;