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Proof step 2 from proof less-01 (previous step)

n0 + m < m0 ⊦ n0 < n, n + m < m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n0 + m < m0 ⊦ m0 = 0, n + m ≠ m0 ∧ ¬ m0 < n + m, n0 ≠ n ∧ ¬ n < n0

Rule argument

Additional information

Used simplifier rules: ls-04: ⊦ m < n ↔ ¬(m = n ∨ n < m);%f: ⊦ m < n → n ≠ 0;