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Proof step 2 from proof less-02 (previous step)

n0 + n1 + n < m ⊦ n < n2, n0 + n1 + n2 < m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n0 + n1 + n < m ⊦ m = 0, n0 + n1 + n2 ≠ m ∧ ¬ m < n0 + n1 + n2, n ≠ n2 ∧ ¬ n2 < n

Rule argument

Additional information

Used simplifier rules: ls-04: ⊦ m < n ↔ ¬(m = n ∨ n < m);%f: ⊦ m < n → n ≠ 0;