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Proof step 4 from proof less-03 (previous step)

n + n0 < m ⊦ m = 0, m0 = n1, n + n0 + n1 ≠ m + m0 ∧ ¬ m + m0 < n + n0 + n1, m0 ≠ n1 ∧ ¬ n1 < m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
n + n0 < m, n1 < m0 ⊦ m = 0, m0 = n1, m0 = 0, n + n0 + n1 ≠ m + m0 ∧ ¬ m + m0 < n + n0 + n1

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0;