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Proof step 2 from proof less-04 (previous step)

m + m0 < n + n0 ⊦ m0 < n0, m < n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m + m0 < n + n0 ⊦ n + n0 = 0, m ≠ n ∧ ¬ n < m, m0 ≠ n0 ∧ ¬ n0 < m0

Rule argument

Additional information

Used simplifier rules: ls-04: ⊦ m < n ↔ ¬(m = n ∨ n < m);%f: ⊦ m < n → n ≠ 0;