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Proof step 5 from proof less (
previous step
)
n < m, n < m ∧ n0 < m0 → (n + n0 < m + m0 ↔ true) ⊦ m = 0, n + n0 ≠ m + m0 ∧ ¬ m + m0 < n + n0, m0 ≠ n0 ∧ ¬ n0 < m0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
n < m, n0 < m0 → n + n0 < m + m0 ⊦ m = 0, m0 ≠ n0 ∧ ¬ n0 < m0, n + n0 ≠ m + m0 ∧ ¬ m + m0 < n + n0
Rule argument
Additional information