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Proof step 7 from proof less (previous step)

n + n0 = m + m0, n < m, n0 < m0 → n + n0 < m + m0 ⊦ m = 0, m0 ≠ n0 ∧ ¬ n0 < m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
n + n0 = m + m0, n < m ⊦ m = 0, m0 ≠ n0 ∧ ¬ n0 < m0, n0 ≠ m0 ∧ ¬ m0 < n0

Rule argument

Additional information

Used simplifier rules: l: ⊦ m + n < m + n0 ↔ n < n0;%ref: ⊦ ¬ n < n;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%ls-04: ⊦ m < n ↔ ¬(m = n ∨ n < m);