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Proof step 2 from proof numeral-1 (previous step)

⊦ n +1 = m ↔ n = m -1, m = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: succ: ⊦ m +1 = m + 1;%pred: ⊦ (m + 1)-1 = m;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%psh-03: ⊦ m ≠ 0 → (m -1 = n ↔ m = n +1);