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Proof step 2 from proof numeral-2 (previous step)

⊦ n +1 < m ↔ n < m -1, m = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: succ: ⊦ m +1 = m + 1;%psh-01: ⊦ m < n0 → (n < n0 -1 ↔ n +1 < n0);%psh-04: ⊦ n ≠ 0 → (m < n -1 ↔ m +1 < n);