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Proof step 2 from proof one-04 (previous step)

⊦ m + n = 1 ↔ n = 1 ∧ m = 0, n = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%one-05: ⊦ m ≠ 1 → (m + n = 1 ↔ m = 0 ∧ n = 1);%one-06: ⊦ 1 = m + 1 ↔ m = 0;