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Proof step 3 from proof pe-01 (previous step)

m0 < m ⊦ n0 + (m + n)-1 = ((n0 + m) + n)-1, m = 0

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: m

Additional information

Used simplifier rules: gen: ⊦ ;%succ: ⊦ m +1 = m + 1;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%pred: ⊦ (m + 1)-1 = m;%c: ⊦ m + n = n + m;%eq-01: ⊦ m + n = m + n0 ↔ n = n0;