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Proof step 2 from proof psh-01 (previous step)

m < n0 ⊦ n < n0 -1 ↔ n +1 < n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m < n0 ⊦ n < n0 -1 ↔ n + 1 < n0, n0 = 0

Rule argument

Additional information

Used simplifier rules: succ: ⊦ m +1 = m + 1;%f: ⊦ m < n → n ≠ 0;