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Proof step 3 from proof psh-03 (
previous step
)
⊦ m = m -1 +1, m = 0
Heuristic elimination applied rule insert elim lemma
And obtained the following new goals
Proof step 4
:
⊦ n ≠ 0 → (n0 = n -1 ↔ n = n0 +1)
Rule argument
spec: <toplevel> name: elim seq: ⊦ n ≠ 0 → (n0 = n -1 ↔ n = n0 +1) subst: [n, n0] → [m, n] flags: <rotated> <all paths>
Additional information
Used terms: m, n